Mathematics, 22.04.2021 21:10, susanc5170
A system of equations can be solved by elimination in the table below. 1 5x + 3y = 14 4x - 2y = -2 2 2(5x + 3y) = 2(14) 4x – 2y = -2 5x + 3y = 14 3(4x – 2y) = 3(-2) 3 10x + 6y = 28 4x - 2y = -2 5x + 3y = 14 12x – 6y = -6 4 10x + 6y = 28 12x 6y = -6 Does the system of equations on line 4 have the same solution set as the system of equations on line 1? Why or why not?
A. The system of equations in stel 4 is equivalent to the system of equation in step 1
The systems do not have the same solution set because the same ordered pair does not satisfy both systems.
B. The system of equations in step 4 is not equivalent to the system of equation in step 1.
The systems do not have the same solution because the same ordered pair does not satisfy both systems.
C. The system of equations in step 4 is
equivalentes to the system of equation in step 1
The systems have the same solution because the same ordered pair does satisfie both systems.
D. The system of equations in step 4 is not equivalentes to the system of equation in step 1
The systems have the same solution because the same ordered pair satisfies both systems.
Answers: 2
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A system of equations can be solved by elimination in the table below. 1 5x + 3y = 14 4x - 2y = -2 2...
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