Factor the common factor out of each expression.

8x-40

Arectangle has a perimeter of 24 inches. if the width is 5 more than twice the length, what are the dimensions of the rectangle?

Manuela solved the equation below. what is the solution to manuela’s equation?

Th perimeter of a rectangular garden is 150 feet. the length is 50 feet longer than the width, w. which equation could be used to calculate the width of the garden? a.) 2w+ 2(w-50) =150 b.) 2w+50 + 2w =150 c.) 2(w+50) + w =150 d.) 2w+ 2(w + 50) = 150 need asap. will give brainliest !