can someone answer these quick questions? i will mark brainliest & please do not answer with a link. thanks.

Step-by-step explanation:

a)  Two lines are parallel and KN is transversal.

So, alternate interior angles are equal.

∠LNM =∠JKL

6x + 1 = 25

Subtract 1 from both sides.

6x + 1 - 1 = 25 -1

6x = 24

Divide both sides by 6

6x/6 = 24/6

x = 4°

b) ∠LMN = 3x +11

             = 3*4 + 11

              = 12 + 11

∠LMN = 23°

c)  ∠KJL = ∠LMN    {Alternate interior angles are equal, transversal JM}

∠KJL = 23°

In ΔKLJ,

∠JKL + ∠KLM + ∠LJK = 180°

25 + ∠KLM + 23 = 180

∠KLM + 48 = 180

∠KLM = 180 - 48

∠KLM = 132°

d) In ΔJKL & ΔLMN

∠J = ∠M

∠K=∠N

∠NLM = ∠KLJ     {Vertically opposite angles.

ΔKJL & ΔLMN  are similar triangles

add an image

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841