A cylinder of clay has a radius of 6 cm and a height of 12 cm. If this clay is made into congruent cones with a radius of 3 cm and a height of 8 cm, how many cones could be made with all of the clay? Show work to support how you determined your answer.

So we want to know how much clay did Joseph add after he built the cone. So the formula for the volume of the cone is V=(1/3)*pi*r^2*h where r is the radius and h is height. We know h1=12cm and r1=6cm, r2=6cm and h2=18 cm. So to get the amount of added clay Va we simply subtract the volume of the clay of the first cone V1 from the volume of the second cone V2: Vd=V2-V1=(1/3)*pi*(r1^2)*h1 - (1/3)+pi*(r2^2)*h2. Va=678.24 cm^3-452.39 cm^3= 266.08 cm^3.

Step-by-step explanation:

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