Write \displaystyle y = −x^2 + 12x − 5y=−x2+12x−5 into the form \displaystyle y = a(x − h)^2 + k. y=a(x−h)2+k. GIVEN that h =h=\frac{-b}{2a}2a−b​ and k=k= \fra c{4ac-b^{2}}{4a}4a4ac−b2​

then hh= kk=

FINALLY yy= (x-x− )^{2}2++​

c-   36

taxicab circle radius 9 has 4(9) = 36 points

b.

step-by-step explanation:

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16