AB and BC form a right angle at point B. If A=(-3,-1) and B=(4,4), what is the equation of BC A. X+3y=16
B. 2x+y=12
C. -7x-5y=-48
D. 7x-5=48

(C) -7x − 5y = -48

Step-by-step explanation:

We look for the equation of the line AB

We have then:

y-yo = m (x-x0)

m = (y2-y1) / (x2-x1)

m = (4 - (- 1)) / (4 - (- 3))

m = 5/7

We choose an ordered pair:

(xo, yo) = (4, 4)

Substituting:

y-4 = (5/7) (x-4)

y = (5/7) x-20/7 + 4

7y = 5x - 20 + 28

7y = 5x + 8

y = (5/7) x + 8/7

The equation of the perpendicular line is:

-7x - 5y = -48

the equation of BC is:

(C) -7x - 5y = -48

d

gimmee one of those gold crowns!

~coco

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58