Jeffrey is saving up for a down payment on a car. He plans to invest $2,000 at the end of every year for 4 years. If the interest rate on the account is 2.15% compounding annually, what is the present value of the investment? $7,587.82
$5,033.72
$8,261.72
$15,252.94

step-by-step explanation:

£56

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

75

step-by-step explanation: