Iam having trouble with linear graph equations 2y+x=-5

Make it into slope intercept form which is y=mx+b
subtract x ffrom both sides
2y=-5-x
divide by 2
y=-1/2x-5/2

y=mx+b
m=slope
b=y intercept or where the line passes through the y-axis

now one way is to graph points by subsituting
if x is 0 then y=-5//2
if x=1 then y=-3
if x=-5 then y=0

another way is to find out where the line passes though the y and x axis or the y and x intecepts respectively

the y intercept is when x=0
the x intecept is when y=0

so set each to zero and solve
if x=0
y=-1/2(0)-5/2
y=-5/2
the line passes throught the y axis at -5/2, plot the point (0,-5/2) on the y axis

then set y to zero
0=-1/2x-5/2
add 5/2 to both sides
5/2=-1/2x
multiply -1
-5/2=1/2x
multiply by 2
-5=x
therefor the line passes through tthe x axis at (-5,0)
then draw the line between the 2 points

here is the graph

Do you need with the x value for the minimum? its always between the two intercepts for a parabola