One cubic centimeter (1.0 cm3) of water has a mass of 1.0 ✕ 10−3 kg. (a) determine the mass of 1 m3 of water. incorrect: your answer is incorrect. kg (b) assuming biological substances are 100% water, estimate the mass of a (spherical) cell with a diameter of 1.0 µm. incorrect: your answer is incorrect. kg (c) assuming biological substances are 100% water, estimate the mass of a human kidney. take a kidney to be roughly a sphere with a radius of 4 cm. kg (d) assuming biological substances are 100% water, estimate the mass of a fly. take a fly to be roughly a cylinder 4 mm long and 2 mm in diameter. kg

We are given that the density of water is:

density (d) = 1 x 10^-3 kg / cm^3

Therefore

A. given volume = 1 m^3 , we need to find the mass but before that let us convert the volume into units of cm^3:

volume = 1 m^3 * (100 cm / 1 m)^3 = 1,000,000 cm^3

So the mass is simply density times volume:

mass = (1 x 10^-3 kg / cm^3) * 1,000,000 cm^3

mass = 1,000 kg

B. We are given that the diameter of the sphere is:

diameter = 1.0  µm or 1 x 10^-4 cm

The volume of a sphere can be calculated as:

V = (4/3) π r^3

V = (4/3) π (1 x 10^-4 cm / 2)^3

V = 5.236 x 10^-13 cm^3

So the mass is:

mass = (1 x 10^-3 kg / cm^3) * 5.236 x 10^-13 cm^3

mass = 5.236 x 10^-16 kg = 5.236 x 10^-13 g

C. We are given the radius = 4 cm

The volume of a sphere can be calculated as:

V = (4/3) π r^3

V = (4/3) π (4 cm)^3

V = 268.08 cm^3

So the mass is:

mass = (1 x 10^-3 kg / cm^3) * 268.08 cm^3

mass = 0.268 kg = 268 g

D. We are given the dimensions of the cylinder:

height = 4 mm = 0.4 cm

diameter = 2 mm = 0.2 cm

The volume of a cylinder is calculated as:

V = π r^2 h

V = π (0.2 cm/2)^2 * 0.4 cm

V = 0.0126 cm^3

So the mass is:

mass = (1 x 10^-3 kg / cm^3) * 0.0126 cm^3

mass = 1.26 x 10^-5 kg

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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