If 0° ≤ θ ≤ 90° and cosθ = 11/15 , what is the value of sin (90° - θ)?

The value of is:

Step-by-step explanation:

We are given an angle  "Theta" or θ which lie in the first quadrant i.e.  0°≤θ≤90°

Also we are given cosine of angle theta as:

Now we are asked to find the value of:

We know that:

( Since, the conversion of the angle 90-θ will remain in the same first quadrant

since, 0°≤θ≤90°

-90°≤-θ≤0°

90°-90°≤90°-θ≤90°

Hence,   0°≤90°-θ≤90°

    and as both cosine and sine function are positive in the first quadrant,

so, the conversion gives:

)

Hence, the value of:

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: