Plz . will give double points, comment, and brainliest. plz
abcd and efg are parallel lines
bc = cf
angle bfe =70°
work out the size of the angle marked x.
give reasons for each stage of your working.
(diagram not accurately drawn)

Since ABCD and EFG are parallel, so the angle FBC = angle BFE = 70°
also note that the triangle is an isosceles triangle, so two of its angles will be equivalent
which in this case would be: Angle FBC = Angle CFB
so angle CFB = 70°
As the internal angles of a triangle should add up to 180°, so 70 + 70 + X = 180
X = 180-70-70 = 40°

First subtract 10 from both side
y^2+6y-16=0
(y+8)(y-2)=0
-8 and 2