De bisects ab at c. if ac =8x-23 and cb=3x+22 find x

x = 9.

Step-by-step explanation:

Given  : DE bisects AB at C. If AC =8x-23 and CB=3x+22.

To find :  Find X.

Solution : We have given  DE bisects AB at C.

Bisector : A point which cut the line in to two equal parts.

ACB

AC = CB . ( C  bisect AB)

Plug the values.

8x - 23 = 3x + 23 .

On subtracting both sides by 3x

8x - 23 - 3x  = 22 .

5x - 23 = 22 .

On adding both sides by 23 .

5x = 23 +22 .

5x = 45 .

On dividing both sides by 5 .

x = 9.

Therefore, x = 9.

the image of (6, 9) under a dilation is (4, 6). the scale factor is

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent