Mathematics, 31.08.2019 22:30, dgray4410

20 !
a polynomial function is shown below: f(x) = x3 − 3x2 − 4x + 12
which graph best represents the function?

20 ! a polynomial function is shown below: f(x) = x3 − 3x2 − 4x + 12 which graph best

Answers: 2

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answered: toxsicity

F(x) = x3 − 3x2 − 4x + 12 ( should be f(x) = x^3 − 3x^2 − 4^x + 12 )

is a cubic function because its highest power of x is 3. Because x^3 is positive, the graph starts in Quadrant III and ends in Quadrant I.

The y-intercept is (0,12).

The greatest possible number of real roots is 3; the minimum number of real roots is 1.

Note that x=3 is a root of this function f(x) = x^3 − 3x^2 − 4^x + 12. Thus, (3,0) is an x-intercept. x=2 and x= -2 are also roots and lead to zero y-intercepts.

Can you now choose the correct graph?

If not, ask questions and I'll try to help you further.

answered: googoomylizard

the graph in the attached figure

Step-by-step explanation:

we have

$f(x)=x^{3}-3x^{2}-4x+12$

Using a graphing tool

The x-intercepts of the function are the points (-2,0),(2,0),(3,0) (values of x when the value of the function is equal to zero)

The y-intercept of the function is the point (0,12) (values of the function when the value of x is equal to zero)

the graph in the attached figure

20 ! a polynomial function is shown below: f(x) = x3 − 3x2 − 4x + 12 which graph best represents

answered: Guest

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answered: Guest

the formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

from a table we have

$x_1=-4,\ y_1=7\\\\x_2=-2,\ y_2=5$

substitute:

$m=\dfrac{5-7}{-)}=\dfrac{-2}{2}=-1$

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

answer: the function g(x) has the greatest slope.
The functions, f(x) and g(x) , are shown below. x f(x) -4 7 -2 5 0 3 2 1 4 -1 which function has the

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20 !
a polynomial function is shown below: f(x) = x3 − 3x2 − 4x + 12
which graph best...