Solve for d in the following equation: c(ad)+ x=bd+ad(yz)

c(ad)+x=bd+ad(yz) step 1: first we separate x and y , so x=bd+adyz-cad Note: i) (yz) can be written as yz ii) when the term cad comes to right side it becomes -cad, because it is with the addition operation in the left hand side. (it is a general rule of mathematics) step 2: then we take out the common data from the above equation, so the common term for all terms in the right hand side is 'd', so, x=d(b+ayz-ca) step 3: now we need to find d, so d =x/b+ayz-ca Note: the term (b+ayz-ca) becomes the divisor of x since it is in the multiplication term on right hand side. so when moving it to left side, it becomes a division operator. (it is also a general rule of mathematics) so d =x/b+ayz-ca

The answer is lol i dont know