If an arrow is shot upward on mars with a speed of 58 m/s, its height in meters t seconds later is given by y = 58t − 1.86t2. (round your answers to two decimal places.) (a) find the average speed over the given time intervals.
i. t= [1, 2]
ii. t=[1, 1.5]
iii. [1, 1.1]
iv. [1, 1.01]

The average velocity at different time interval can be evaluated by using average velocity formula. So, at time interval [1,2] the average velocity is 52.42m/sec, at time interval [1,1.5] the average velocity is 53.35m/sec, at time interval [1,1.1] the average velocity is 54.09m/sec, and at time interval [1,1.01] the average velocity is 54.26m/sec.

Given :

The average velocity is given by the formula:

So, at the time interval, t = [1,2], the average velocity will be:

Now, at the time interval, t = [1,1.5], the average velocity will be:

Now, at the time interval, t = [1,1.1], the average velocity will be:

Now, at the time interval, t = [1,1.01], the average velocity will be:

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answer:

sometimes

*i think

c is the correct answer

step-by-step explanation: