Mathematics, 03.10.2019 04:00, potternatalie90
Differentiate the following function: u = cube root of (t^2) - 6sqrt(t^3)
Answers: 1
![\sqrt[n]{x^m}=x^\frac{m}{n}](/tpl/images/0285/2397/e7325.png)
![u=\sqrt[3]{t^2}-6\sqrt[2]{t^3}](/tpl/images/0285/2397/c846e.png)
![u=\sqrt[3]{t^2}-6t\sqrt[2]{t}](/tpl/images/0285/2397/bc7c7.png)
![\frac{dt}{du}=\frac{2}{3\sqrt[3]{t}}-\frac{3t}{\sqrt{t}}](/tpl/images/0285/2397/10bb5.png)
![\frac{dt}{du}=\frac{2\sqrt[3]{t^2}}{3\sqrt[3]{t^3}}-\frac{3t\sqrt{t}}{\sqrt{t^2}}](/tpl/images/0285/2397/7df8e.png)
![\frac{dt}{du}=\frac{2\sqrt[3]{t^2}}{3t}-\frac{3t\sqrt{t}}{t}](/tpl/images/0285/2397/6bf7d.png)
![\frac{dt}{du}=\frac{2\sqrt[3]{t^2}}{3t}-\frac{9t\sqrt{t}}{3t}](/tpl/images/0285/2397/a8fdd.png)
![\frac{dt}{du}=\frac{2\sqrt[3]{t^2}-9t\sqrt{t}}{3t}](/tpl/images/0285/2397/0d8e0.png)
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Differentiate the following function: u = cube root of (t^2) - 6sqrt(t^3)...
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