What is the greatest possible integer value of x for which square root of x-5 is an imaginary number?

x = 4

Step-by-step explanation:

Value of will be imaginary. if =

Since is not defined to square root will be imaginary.

In this question greatest possible integer value of x has been asked.

(x-5) will be negative if x<5 and the maximum value of x will be 4 above which (x-5) will be greater than zero.

Therefore, x = 4 is the maximum integer value of x for which square root of (x-5) is an imaginary number.