$22,102 is invested, part at 11% and the rest at 7%. if the interest earned from the amount invested at 11% exceeds the interest earned from the amount invested at 7% by $913.46, how much is invested at each rate? (round to two decimal places if necessary.)

X + y = 22,102
.11x = .07y + 913.46  =      x= (7/11)y + 8304.18

((7/11)y + 8304.18) + y = 22,102

(18/11)y = 13797.82

y= 13797.82/(18/11)

y=8432.00 

8,432.00 dollars are invested at 7%
13,670.00 dollars are invested at 11%

Check
.07 x 8432=  590.24
.11 x 13,670 = 1503.70

1503.70 - 590.24 = 913.46

the law of definite proportions states samples of a compound will always contain the same proportion of elements by mass. in other words, a given compound will always contain the same elements in the same proportions by mass.the law of multiple proportions states when two elements combine with each other to form more than one compound, then the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.