Aflat rectangular piece of aluminum has a perimeter of 70 inches. the length is 11 inches longer than the width. find the width. a. 34 inches b. 35 inches c. 23 inches d. 12 inches

perimeter = 2L +2w

L = w+11

70 = 2(w+11) +2w

70 = 2w+22+2w

70= 4w + 22

48 = 4w

w=48/4 = 12

width = 12

length = 12+11 = 23

2x12 = 24

2x23 = 46

46+24 = 40

 length = 23 inches, width = 12 inches

Answer is D

The answer is the option D

Step-by-step explanation:

we know that

The perimeter of a rectangle is equal to

where

L is the length side of the rectangle

W is the width side of the rectangle

In this problem we have

so

------> equation A

------> equation B

Substitute equation B in equation A and solve for W

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

900 degrees

step-by-step explanation: