Wolfgang and heinrich worked as electricians at $14 and $12 per hour respectively. one month wolfgang worked 10 hours more than heinrich. if their total income for the month was $3520, how many hours did each work during the month?

Let us say that:

x = hours worked by Wolfgang

y = hours worked by Heinrich

So that:

x = y + 10

14 x + 12 y = 3520

By combining the two equations:

14 (y + 10) + 12 y = 3520

14 y + 140 + 12 y = 3520

26 y = 3380

y = 130 hours

x = y + 10 = 140 hours

So Wolfgang worked 140 hours while Heinrich worked 130 hours.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47