Graph y = 3x - 3 and label the x- and y-intercepts. my (0,3)

tell the slope of a line that contains the points (5, -3) and (7,3) my 6/2

it's the start of the school year, so i'm pretty !

The slope-intercept form of the linear function is y = m x + b , where m is the slope and b is y-intercept.
Here we have: y = 3 x - 3
a ) When y = 0
0 = 3 x - 3
- 3 x  = - 3
x = ( - 3 ) : ( - 3 ) 
x = 1
When x = 0
y = 3 * 0 - 3 
y = - 3
So x - intercept is ( 1, 0 ) and y-intercept is ( 0, - 3 ).
b ) The slope:
m = ( y2 - y1) / ( x2 - x1 ) = 
= ( - 3 - 3 ) / ( 5- 7 ) = ( - 6 ) /( - 2 ) = 6 / 2 = 3
The slope m = 3 . 

It creates dogx^2 and then flip your answer and multiply by 2

What is the question?