Maya runs 100m in 13.4s and amy can run 100m in 14.1s. if amy were to finish a 100m race at the same time as maya, how much of a head start, in meters, will amy need? what information is known and unknown? and what proportion can you write to solve this problem?

In this case we will use the general equation:

 d = s t (distance = speed*time)

Therefore

Distance Amy can run in 13.4s:

d = (100m/14.1s)*(13.4s)

d = 95.04meters

Headstart needed = total distance - distance run in 13.4s (time Maya runs 100m)

headstart needed = 100-95.04 = 4.96meters

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61

step-by-step explanation:

let's assume

number of candles set =x

price of of x candles =p(x)

we are given

a candle maker prices one set of scented candles at $10 and sells an average of 200 sets each week

so, we get point as (200,10)

he finds that when he reduces the price by $1, he then sells 50 more candle sets each week

so, we can find slope

now, we can use point slope form of line

now, we can plug values

we can use point

and find b

now, we can plug it back

and we get

now, we can find revenue

we know that

revenue = price*quantity

so, we get