I'm not sure if i did these correct. i got ( no solution ) for both.

> absolute value inequalities<

7|4a-6|< 42

second inequality

3|z+4|-13 < -1

7|4a-6| < 42
|4a-6| < 42/7
|4a-6| < 6
remove the absolute value brackets by solving for both +/-
4a-6 < 6
4a < 12
a < 12/4
a < 3

now negative inside

-(4a-6) < 6
-4a +6 < 6
-4a < 0
equality sign flips direction when multiply or divide by a negative.
a > 0

So "a " has to be both greater than zero and less than 3.
0 < a < 3

Theirhgghh

A. is the answer in this question