Abowl contains 25 balls numbered 1 to 25. a ball is drawn and its number is noted. without replacing the first ball, another ball is drawn. the probability that the numbers on both balls are odd numbers is ?

Using the hypergeometric distribution, it is found that there is a 0.26 = 26% probability that the numbers on both balls are odd numbers.

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The balls are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

In which:

Combinations formula:

is the number of different combinations of x objects from a set of n elements, given by the following formula.

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In this question:

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The probability that the numbers on both balls are odd numbers is ?

This is P(X = 2). Thus

0.26 = 26% probability that the numbers on both balls are odd numbers.

A similar problem is given at link

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!