Neil has been running a tutoring business since 2005. he charges a monthly fee for weekly tutoring sessions and a phone line. each year, he has increased his fee by the same amount. the table shows what neil charged each customer for two given years of his business:

year annual tutoring fee
2005 $1200
2008 $1350

a. what is the rate of change and initial value for neil’s business? how do you know?
b. write an equation in slope-intercept form to represent the fees that neil charges each year

We are measureing increase per year

so

change in price divided by change in years

1350-1200=150=change in price
2008-2005=3 years=chnage in years

so total is 150dollars/3yrs=50dollars/1yr

A. rate of change is 50 dollars per year
I know because math and also (1350-1200)/(2008-2005)=$50/yr

B.
hmm
the slope is 50
started in 2005
so that is year 0, or is it year 1
do we measuer years passed or which year is it?
let's say how many elapsed

alrighty,s

y=mx+b
m=slope
b=y intercept (value of y when x=0)
when x=0 is at 2005
that is the price is 1200
so b=1200

y=50x+1200

It is 198,87032,750 + 375 = 33145 so, we take the 6% and we make it a decimal (0.6) and multiply that, then that is your answer