Evaluate each using the values given n-n-(n+n-m); use m=6,and n=-10

In order to evaluate the expression, certain order should be followed. We should start by evaluating terms in brackets, then move on to any multiplication or division and finally evaluate addition and subtraction.

In the given term, we will start by evaluating the term in brackets and then evaluate the subtraction outside the bracket.

It is also good to know the following (note the signs and the resulting operation):
2 + 2 = 4
2 - 2 = 0
2 + -2 = 2 - 2 = 0
-2 -2 = -4
-2 + -2 = -2 -2 = 4
-2 + 2 = 0

Now for the term we have:
 n-n-(n+n-m) where m = 6 and n = -10
Substituting in the expression, we will get:
-10 - -10 - (-10 + -10 - 6)
which can be written as:
-10 + 10 - (-10 - 10 - 6)
evaluating the term in brackets we get:
-10 + 10 - (-26)
which can be written as:
-10 + 10 + 26 = 0 + 26 = 26

Therefore, the final result is 26.

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)