3sets of traffic lights on route. there is a fifty fifty chance of lights being te or green. what are chances of getting 3 consecutive green lights

1/6

Step-by-step explanation:

Let probability of green be G and The be T

There are 6 possible outcome

GGG

GGT

GTT

TTT

TGT

BGG

Probability of it being green

=50/100= 1/2

Probability of 3 consecutive G

= GGG= 1/2 *1/2 *1/2

=1/6

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

the answer is b.)

< 1=< 2