![z = r (cos \theta + i sin \theta) \\ \\ \sqrt[3]{z} = \sqrt[3]{r}(cos \frac{\theta +360k}{3} +i sin \frac{\theta +360k}{3} ) , k = 0,1,2](/tpl/images/0329/2628/75e47.png)
![\sqrt[3]{-27} = \sqrt[3]{27} (cos \frac{180 +360k}{3} +i sin \frac{180 +360k}{3} ) ](/tpl/images/0329/2628/d94ee.png)
Find the cube root of -27 that graphs in the first quadrant.
3(cos? +isin? ) use degree measur...
Mathematics, 17.10.2019 20:30, genyjoannerubiera
Find the cube root of -27 that graphs in the first quadrant.
3(cos? +isin? ) use degree measure.
Answers: 2
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