Mathematics, 29.01.2020 21:45, zyairemitchell44
Differentiate y equals the quotient of the quantity 1 plus sine x and the quantity 1 minus cosine x.
–1
–2csc(x)sec(x)
2csc(x)sec(x)
the quotient of negative 1 times sine x plus cosine x minus 1 and the square of the quantity 1 minus cosine x
Answers: 3
![\bf sin^2(\theta)+cos^2(\theta)=1\\\\ -------------------------------\\\\ y=\cfrac{1+sin(x)}{1-cos(x)}\impliedby \textit{using the quotient rule} \\\\\\ \cfrac{dy}{dx}=\cfrac{cos(x)[1-cos(x)]-[1+sin(x)]sin(x)}{[1-cos(x)]^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{cos(x)-cos^2(x)-sin(x)-sin^2(x)}{[1-cos(x)]^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{cos(x)-sin(x)-[cos^2(x)+sin^2(x)]}{[1-cos(x)]^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{cos(x)-sin(x)-\boxed{1}}{[1-cos(x)]^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{-sin(x)+cos(x)-1}{[1-cos(x)]^2}](/tpl/images/0483/3783/69a39.png)
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Differentiate y equals the quotient of the quantity 1 plus sine x and the quantity 1 minus cosine x....
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