Jack plays on a basketball team after school every third day of the month. he babysits his younger brother after school every seventh day of the month. how many times during a 30 day mark if any will jack have a conflict between basketball and babysitting? explain

1 conflict a month.

Step-by-step explanation:

To calculate this you just have to calculate the smallest common multiple by multiplying both numbers:

7x3=21

The 21st day of the month he would have to babysit and play basketball after school, so he would have a conflict between the two of them.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)