Atunnel is in the shape of a parabola. the maximum height is 50 m and it is 10 m wide at the base as shown below. what is the vertical clearance 2 m from the edge of the tunnel?

Refer to the figure shown below.

Because the maximum height of the parabola is 50 m, its equation is of the form
y = ax² + 50

This equation places the vertex at (0,50). The constant a should be negative for the vertex to be the maximum of y.

The base of the parabola is 10 m wide. Therefore the x-intercepts are (5,0) and (-5,0).
Set x=5 and y=0 to obtain
a(5²) + 50 = 0
25a = -50
a = -2

The equation of the parabola is
y = - 2x² + 50

At 2 m from the edge of the tunnel, x = 5 - 2 = 3 m.
Therefore the height of the tunnel (vertical clearance) at x = 3 m is
h = y(3)
   = -2(3²) + 50
   = - 18 + 50
   = 32 m

32 m

Maybe fx = lxl because of the way the x is positioned is that what he