~only answer if you know for sure~
you bought a car for $20,000. you have owned it for one year, and it is now worth $16,000. what is the percent decrease in your car's value?
20%
25%
80%
125%

Option A. 20%

Step-by-step explanation:

Since the cost price of the car when it was new = $20000

After one year car value $16000.

We have to calculate the depreciation in the price or my car.

So decease in the car's value = 20000-16000 = $4000

Since cost price of the car was = $20000

therefore % decrease decrease in the price will be = (decrease in price/cost price)×100 = (4000/20000)×100 = 20%

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

no idea

step-by-step explanation: