What is the surface area of the right cone with a radius of 8 and height of 15?

a. 184 pi units^2

b. 304 pi units^2

c. 248 pi units^2

d. 496 pi units^2

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice