In simplest radical form, what are the solutions to the quadratic equation 6 = x^2 – 10x?

6 = x² - 10x. Re-write it:

x² - 10 - 6 = 0. This is a quadratic equation (ax²+bx+c=0) and the solutions are given by the following formula:

x' = [-b + √(b²-4ac)]/2a         and x" = [-b - √(b²-4ac)]/2a      

(for your info a =1, b= -10, c= - 6). Plug in the related values and you'll find:

x' =5+√31   and x" = 5-√31