The equation of line ef is y = 1 over 2 x + 6. write an equation of a line parallel to line ef in slope-intercept form that contains point (0, −2).

The given equation of the line is,
         y = x/2 + 6

The given equation is slope-intercept form where the general form is,
       y = mx + b
where m is the slope and the y-intercept is b.

From the equation it can be identified that m = 1/2 and b = 6. The slope of the line that is parallel to the given equation is also 1/2. Thus, using the slope-point form of the forming the equation,

      y - y₁ = m(x - x₁)

Substituting the known values,
   y - (-2) = (1/2)(x - 0)
    y + 2 = x/2

Transposing the constant to the right-hand side of the equation the equation becomes,
   y = x/2 - 2

ANSWER: y = x/2 - 2

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