The function f(x) = –3x2 + 36x – 119 written in vertex form is f(x) = –3(x – 6)2 – 11. which statements are true about the graph of f(x)?

check all that apply.
the axis of symmetry is the line x = 6.
the vertex of the graph is at (–6, –11).
the parabola has a minimum.
the parabola opens down.
the value of h, when the equation is written in vertex form, is positive.

F(x)=a(x-h)²+k
the axis of symmetry is x=h
the vertex is (h,k)
if a<0, the parabola opens down and has a max
if a>0, the parabola opens up and has a minimum

so

f(x)=-3(x-6)²-11
a=-3<0 so it opens down and has a maximum
h=6, the axis of symmetry is x=6
k=-11
vertex is (6,-11)

so answers are
axis of symmetry is the line x=6
the parabola opens down
the value of h, when the equation is written in vertex form, is positive

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