|3−10|−(12÷4+2)^2

can someone work this out step by step for me so i can fully understand the process

Ok so follow PEMDAS 
|3−10|−(12÷4+2)^2
|-7|-(3+2)^2
7-(5)^2
7-25
-18

Using PEMDAS you'd start with the parentheses 
(12/4+2)
(3+2)
(5)^2
then square it, but dont forget about the negative
5^2=25 
|3-10|-25
then 3-10 is -7 but the absolute value makes it positive
so
7-25 would turn out to be -18