If 3 consecutive integers sum to 63, the largest of the 3 = ?

This problem states that the sum of 3 consecutive integers is 63 and it asks us to find the largest integer.

Three consecutive integers can be represented as followed.

X → first integer

X + 1 → second integer

X + 2 → third integer

Since the sum of our three consecutive integers is 24, we can write an equation.

X + X + 1 + X + 2 = 63

We can simplify our equation on the left and it will read...

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

the answer is b.)

< 1=< 2