Mathematics, 09.01.2020 16:31, alinton06
Arectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. find the area of the rectangle.
3 to the 2 over 3 power inches squared
3 to the 8 over 3 power inches squared
9 inches squared
9 to the 2 over 3 power inches squared
Answers: 3
![\sqrt[3]{81}](/tpl/images/0448/5755/ec017.png)
inches and a width of 
power inches. We are asked to find the area of given rectangle.![\text{Area of rectangle}=\sqrt[3]{81}\times 3^{\frac{2}{3}}](/tpl/images/0448/5755/a6978.png)
as:![\text{Area of rectangle}=\sqrt[3]{3^4}\times 3^{\frac{2}{3}}](/tpl/images/0448/5755/98354.png)
![\sqrt[n]{a^m}=a^{\frac{m}{n}}](/tpl/images/0448/5755/09d57.png)
, we can write ![\sqrt[3]{3^4}=3^{\frac{4}{3}}](/tpl/images/0448/5755/a751e.png)
.
, we will get:
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Arectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches....
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