Agame is biased such that the choices a-j have the following probabilities of winning: a 5% b 10% c 15% d 5% e 5% f 25% g 10% h 10% i 10% j 5% if you chose the letters d and h for 20 turns, how many times are you most likely to win? 1 2 3 4 5

Since we have chosen 2 letters, then the total probability of winning the game is the sum of the probabilities of each letter. Therefore:

Total probability of winning = Probability of D + Probability of H

Total probability of winning = 5% + 10%

Total probability of winning = 15%

Since we are playing the game for 20 turns, therefore out of those 20 games, we will win 15% of the time. So:   

15% = 0.15

Winning times = 0.15 * 20

Winning times = 3

Therefore we have a chance or probability to win at least 3 games out of 20 turns.

plz yuo

step-by-step explanation:

probably .5

i can on others if necessary.