Mathematics, 03.12.2019 14:31, dontworry48

1. describe how factoring a quadratic expression ax2 + bx + c, where a ≠ 1, is different from factoring x2 + bx + c.

2. two students factored 2x2 + 6x – 20. keiko said that the factorization was (2x – 4)(x + 5). ray gave the factorization as (x – 2)(2x + 10). confirm that both of these factorizations are correct. then explain why they are not complete.

3. explain the relationship between the factors of a quadratic expression, the roots of the related quadratic equation, and the x-intercepts of the graph of the related function.

Answers: 2

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1. Factoring a quadratic expression ax2 + bx + c, where a ≠ 1, is different from factoring x2 + bx + c because for the former type of expression you have to factor out the value of "a". Then, proceed to the factoring steps as usual.

2. To confirm the equations to be equal with the parent function we do as follows:
(2x – 4)(x + 5) = 2x^2 + 10x - 4x - 20 = 2x^2 + 6x -20
(x – 2)(2x + 10) = 2x^2 +10x - 4x -20 = 2x^2 +6x - 20

3. The roots of the quadratic expression represents the values of x that would satisfy the expression. The x-intercepts are the values of x when y is equal to zero, it is where the plot touches intersects the x-axis.

answered: ayoismeisalex

1. Dividing the expressions ax^2+bx+c by a is a different step.

2. Yes, both of these factorization are correct. They are not complete because they can be factored further.

3. The roots of the related quadratic equation are the x-intercepts of of the related function and factors of the expression are difference of x and roots of the related quadratic equation.

Step-by-step explanation:

To factorize the quadratic expressions ax^2+bx+c first we divide it by a. Then we factorize it same as .

It means all the steps of factoring a quadratic expressions ax^2+bx+c and are same except the first step, i.e., divide the expressions by a.

The given quadratic expression is

P(x)=2x^2+6x-20

$(2x-4)(x+5)=2x(x+5)-4(x+5)\Rightarrow 2x^2+10x-4x-20=2x^2+6x-20=P(x)$

$(x-2)(2x+10)=x(2x+10)-2(2x+10)\Rightarrow 2x^2+10x-4x-20=2x^2+6x-20=P(x)$

The product of factors is equal to the given expression. It means both of these factorization are correct.

They are not complete because they can be factored further.

(2x-4)(x+5)=2(x-2)(x+5)

(x-2)(2x+10)=(x-2)2(x+5)

If the factored form of a quadratic expression is defined as

(x-a)(x-b)

Then the related quadratic equation is

(x-a)(x-b)=0

x=a,b

The roots of the quadratic equation are a and b.

The related function is

f(x)=(x-a)(x-b)

The x-intercepts of the function are a and b because at x=a and x=b the value of function is 0.

The roots of the related quadratic equation are the x-intercepts of of the related function and factors of the expression are difference of x and roots of the related quadratic equation.

answered: Guest

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

answered: Guest

Many things that seem threatening in the dark become welcoming when we shine light on them