Circle p has center p(2,0) and a radius 20 circle q has center q(0,4) and a radius of 2

The solution would be like this for this specific problem:

Given:

(a)  Describe the rule for translating center Q onto center P.

            center P(2, 0)
            center Q(0, 4)

You would require adding 2 units in x axis, and subtract 4 units on y axis

(b)  Determine the scale factor for dilating circle Q so that it has the same radius as circle P.

P radius 20, Q radius 2, radius * 10 = radiusP, so the scale factor is 10.

(c)   Are circles P and Q similar? Explain your answer.

They are the same since there exists a similarity transformation (translation, dilation) among them.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!