Given b = 4 and h = 1, what is the equation of the graph if the parent function is y = sqrt x?
a. y = sqrt (4x - 4)
b. y = sqrt (4x + 4)
c. y = - sqrt (4x - 4)
d. y = - sqrt (4x + 4)

To solve this problem, we make use of the formula:

y = a sqrt (b (x – h)) + k                  ---> 1

Since we are given the parent function:

y = sqrt (x)                                          ---> 2

Then this automatically means that:

a = 1       and        k = 0

So going back to equation 1 at a = 1 and k = 0:

y = 1 sqrt (b (x – h))

Since it is given that, b = 4            and        h = 1, therefore:

y = sqrt (4 (x – 1))

y = sqrt (4 x – 4)

A. y = sqrt (4 x – 4)

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the answer is thin because within context, the stanza concludes the and frail tone the people have toward each other, and the fact that it would be thin, makes the most sense compared to "pliable" or "not hard or firm to the touch". hope this , good luck.

step-by-step explanation:

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