Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. based on this assumption, the volume of the flask is cubic inches. if both the sphere and the cylinder are dilated by a scale factor of 2, the resulting volume would be times the original volume.

options for the first blank are: 20.22, 35.08, 50.07, or 100.11

options for the second blank are: 2, 4, 6 or 8

1) Calculate volume of each figure using according formulas.
You should get:
Sphere: 47.71in^3
Cylinder: 2.36in^3
Now let's add, and you should get 50.07.

2) Let's dilate the dimensions/flask by 2 (multiply by 2)

4.5 * 2 = 9
1 * 2 = 2
3 * 2 = 6

Now with these dimensions you should get:
Sphere: 381.7in^3
Cylinder: 18.85in^3
This should add up to 400.55in^3

Divide new by original. 400.55 / 50.07 = 8

So it is 8 times larger.

Note: Everything is rounded. So it ain't exact.

Brainliest pls for this work

Ithink if im not mistaking b is -3 but im not a 100% sude

A. p = 2(l + w)p/2 - l = ww = p/2 - l b. while isolating the variable w in the equation, i first divided both sides by 2 and then i subtracted l from both sides. i hope this .