Theo started to solve the quadratic equation (x + 2)2 – 9 = –5. he added 9 to both sides and the resulting equation was
(x + 2)2 = 4. next, he took the square root of each side.

which was the resulting equation of that step?

square root of (x+2)^2 = x+2

square root of 4 = 2

so equation will now be x+2 =2

( x + 2 ) = 2

Step-by-step explanation:

Theo started to solve the quadratic equation

( x+2 )² - 9 = -5

He added 9 to both sides

( x + 2 ) ² -9 + 9 = - 5 + 9

         ( x + 2 )² = 4

Now he took the square root  of each side

( x + 2 ) = 2

Therefore, resulting equation will be ( x + 2 ) = 2

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

the barter