How many 3 digit numbers can be made if no digit is repeated and the number can not begin with a zero?

digit #1 - 9 numbers (1-9)

digit #2 = 9 numbers (0-9 minus the first digit)

digit #3 = 8 numbers ( 0-9 minus the first 2 digits)

9*9*8 = 648 combinations

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

investment b is an ordinary annuity with $3,909.64 in the account after one year.

step-by-step explanation: