You inherit one hundred thousand dollars. you invest it all in three accounts for one year. the first account pays 4% compounded annually, the second account pays 3% compounded annually, and the third account pays 2% compounded annually. after one year, you earn $3,650 in interest. if you invest five times the money in the account that pays 4% compared to 3%, how much did you invest in the 4% account?

Let x = amount invested in the 1st account
      y = amount invested in the 2nd account
      z =  amount invested in the 3rd account

Because the total investment is $100,000, therefore
x + y + z = 100,000             (1)
Interest earned in one year from the accounts is $3,650, therefore
0.04x + 0.03y + 0.02z = 3,650
or
4x + 3y + 2z = 365,000      (2)

Because x = 5y, therefore obtain these 2 equations:
5y +y +z = 100,000
or
6y + z = 100,000          (3)
4*(5y) +3y + 2z = 365,000
or
23y + 2z = 365,000      (4)

Substitute z=1000,000 - 6y from (3) into (4).
23y + 2(100,000 - 6y) = 365,000
23y + 200,000 - 12y = 365,000
11y = 165,000
  y = $15,000
Therefore
  x = 5y = $75,000
  z = 100,000 - 6y = $10,000

The amounts invested are
1st account: $75,000
2nd account: $15,000
3rd account: $10,000