Determine the discriminant for the quadracic equation 0=-2x^2+3. based on the discriminant value, how many real number solutions does the equation have?
discriminant = b^2-4ac
? real number solutions

We are gonna use the formula "Discriminant = b^2-4ac" here to determine the discriminant. We have the value of a=-2; b=0; and c=3. Substituting the values to the formula, we can get the discriminant which is 24. We will then use  the rule of discriminant in this problem: 
If b² - 4ac > 0, there are two real number solutions  
If b² - 4ac = 0, there is one real number solution  
If b² - 4ac < 0, there are two imaginary number solutions  
Therefore, we can conclude that there will be two real numbers solutions since the discriminant is greater than 0.