An arrow is shot upward with a velocity of 64 feet per second. using the formula h(t)=64t-16t^2, how long after the arrow is released does it hit the ground?

After the 4 second arrow is released, it will hit the ground.

Step-by-step explanation:

Consider the provided formula.

We need to find how long after the arrow is released does it hit the ground.

If the arrow hit the ground that means the value of h(t)=0.

Substitute the value of h(t)=0 and solve the equation as shown.

Now use zero product rule: If ab=0 then either a=0 or b=0

Hence, after the 4 second arrow is released, it will hit the ground.

the square root of what number? if you add that, then someone will probably answer the question.

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6