An airline claims that the no-show rate for passengers booked on its flights is less than 6%. of 380 randomly selected reservations, 18 were no-shows. assuming that this data is used to test the airline's claim, find the p-value for the test. 0.3508 0.1499 0.1230 0.0746

The p-value of the test is the calculated probability. Hence, the probability must be 18/380. In simplified terms, this is equal to 0.0474 or 4.74%. This is the p-value of the test. The null hypothesis is p < 6%. According to the test, the p-value is 4.74%. Therefore, the null hypothesis is accepted. 

The answer is not among the choices. The answer must be 0.0474 or 4.74%.

1. 3/6 or 1/22. 1/123. 1/84. 1/105. 2/12 or 1/6